50=3w^2-5w

Solution for 50=3w^2-5w equation:

50=3w^2-5w

We move all terms to the left:

50-(3w^2-5w)=0

We get rid of parentheses

-3w^2+5w+50=0

a = -3; b = 5; c = +50;
Δ = b2-4ac
Δ = 52-4·(-3)·50
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-25}{2*-3}=\frac{-30}{-6}
=+5
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+25}{2*-3}=\frac{20}{-6}
=-3+1/3
$